1 EASY $$\frac{1}{2}\div\frac{1}{2}=$$ $$\frac{1}{4}$$1$$\frac{2}{4}$$$$\frac{0}{0}$$None of the above

 2 EASY $$\frac{1}{2}\div\frac{1}{4}=$$ $$\frac{1}{8}$$$$\frac{1}{4}$$$$\frac{1}{2}$$1None of the above

 3 EASY $$\frac{4}{3}\div\frac{1}{3}=$$

 4 MEDIUM $$\frac{1}{8}\div\frac{1}{4}=$$ $$\frac{1}{2}$$$$\frac{1}{8}$$2$$\frac{1}{4}$$None of the above

 5 MEDIUM $$\frac{1}{3}\div\frac{5}{6}=$$ $$\frac{8}{15}$$$$\frac{2}{5}$$$$\frac{5}{16}$$$$\frac{7}{15}$$None of the above

 6 MEDIUM $$\frac{6}{7}\div\frac{3}{2}=$$

 7 MEDIUM $$\frac{7}{4}\div\frac{4}{7}=$$

 8 HARD $$\frac{5}{7}\div\frac{4}{9}=$$ $$\frac{20}{63}$$$$\frac{28}{45}$$$$\frac{63}{20}$$$$\frac{45}{28}$$None of the above

 9 HARD $$\frac{3}{13}\div\frac{5}{8}=$$

 10 HARD Show that in the diagram below, $$|AX|\cdot|XB|=|CX|\cdot|XD|$$. This is known as the Power of a Point Theorem. foobarbazqux